The solutions of the questions in the principles and practice of arithmetic1856 |
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Strana 49
... afforded to the student by the simple considerations presented to his notice in Article ( 139 ) of the Chapter on Ratio and Proportion . CHAPTER IV . VULGAR FRACTIONS . MISCELLANEOUS QUESTIONS . PAGE 3 THE DOUBLE RULE OF THREE . 49.
... afforded to the student by the simple considerations presented to his notice in Article ( 139 ) of the Chapter on Ratio and Proportion . CHAPTER IV . VULGAR FRACTIONS . MISCELLANEOUS QUESTIONS . PAGE 3 THE DOUBLE RULE OF THREE . 49.
Strana 50
John Hind. CHAPTER IV . VULGAR FRACTIONS . MISCELLANEOUS QUESTIONS . PAGE 96 . ( 1 ) Because of a ticket cost £ 4 . 10s .: 3 16 1 of it 16 cost £ 1 . 10s .: therefore a whole ticket cost £ 1 . 10s . × 16 = £ 24 : whence , the price of ...
John Hind. CHAPTER IV . VULGAR FRACTIONS . MISCELLANEOUS QUESTIONS . PAGE 96 . ( 1 ) Because of a ticket cost £ 4 . 10s .: 3 16 1 of it 16 cost £ 1 . 10s .: therefore a whole ticket cost £ 1 . 10s . × 16 = £ 24 : whence , the price of ...
Strana 51
... that the part of it expressed by 2 3 16-9 7 = 3 8 24 = 24 contains 35 gallons ; therefore the capacity of the vessel 24 is of 35 gallons = 120 gallons . 7 1 7 7 5 ( 10 ) First , + 3-2 MISCELLANEOUS QUESTIONS IN FRACTIONS . 51.
... that the part of it expressed by 2 3 16-9 7 = 3 8 24 = 24 contains 35 gallons ; therefore the capacity of the vessel 24 is of 35 gallons = 120 gallons . 7 1 7 7 5 ( 10 ) First , + 3-2 MISCELLANEOUS QUESTIONS IN FRACTIONS . 51.
Strana 52
... .: then of 3 14 of 1 S. = S. = 6d . 27 × 20 3 7 4 8 3 received by B : whence , C received of the difference of 14 S. and 1 3 2 S. = 3 25 of S. = 5 5 6 S. = 2s . 6d . 2 £ 7 . 4s . + £ 1 . 8s 52 MISCELLANEOUS QUESTIONS IN FRACTIONS .
... .: then of 3 14 of 1 S. = S. = 6d . 27 × 20 3 7 4 8 3 received by B : whence , C received of the difference of 14 S. and 1 3 2 S. = 3 25 of S. = 5 5 6 S. = 2s . 6d . 2 £ 7 . 4s . + £ 1 . 8s 52 MISCELLANEOUS QUESTIONS IN FRACTIONS .
Strana 53
... hour part = - 1 12 16 therefore B and C in 1 hour can together do 7 = ; or , they can do 7 4 × 9 = 144 144 9 = 1 12 = : 48 1 + 36 48 of it in 94 hours . are is = 1 ( 20 ) The parts filled MISCELLANEOUS QUESTIONS IN FRACTIONS . 53.
... hour part = - 1 12 16 therefore B and C in 1 hour can together do 7 = ; or , they can do 7 4 × 9 = 144 144 9 = 1 12 = : 48 1 + 36 48 of it in 94 hours . are is = 1 ( 20 ) The parts filled MISCELLANEOUS QUESTIONS IN FRACTIONS . 53.
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The Solutions of the Questions in the Principles and Practice of Arithmetic John Hind (M.A.) Úplné zobrazenie - 1856 |
Časté výrazy a frázy
ALFRED GATTY amount of 100 Appendix area of field BOOK bush Cambridge cent Church of England circle circular sector cloth CONIC SECTION containing cube root cubic inches decimal required discount dwts English Notes Fcap Fellow and Tutor fraction required Furneux Pelham gallons Gothick Grammar School greatest common measure GREEK Head Master hundred Illustrations income JAMES TATE King Edward's School late Fellow LATIN length Manual MISCELLANEOUS QUESTIONS morocco nearly number required places of decimals price 48 prime cost PSALMS quotient reap remainder required fraction required number required stock required sum retail price Second Edition semi-sum sewed Sidney Sussex College solid content solid feet solid ft square links square root square yards sum due sum required tons Trinity College Verse vols volume VULGAR FRACTIONS W. F. HOOK whence
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