 | Daniel Adams - 1861 - Počet stránok 452
...not right-angles ; multiply the length of one side by the shortest distance to the side opposite. To find the area of a trapezoid, multiply half the sum of the parallel sides by the shortest distance between them. A trapezoid is a figure, like the one iu the annexed diagram, bounded... | |
 | Alfred Newsom Niblett - 1861 - Počet stránok 204
...parallel. £_ j \ NB—In this figure the dotted lino shows the perpendicular height. RULES. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Or, half the sum of the sides multiplied by their distance will... | |
 | Thomas Kentish (of London.) - 1861 - Počet stránok 372
...quadrilateral that has only one pair of its sides parallel is called a trapezoid. To find its area, multiply the sum of the parallel sides by the perpendicular distance between them, and take half the product— that is, add AB to CD, multiply by mn, and divide by 2. 106. A quadrilateral... | |
 | Oliver Byrne - 1863 - Počet stránok 600
...find the area of a trapezoid, or a quadrangle, two of whose opposite sides are parallel. — Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Required the area of the trapezoid ABCD, whose sides AB and DC are... | |
 | William Frothingham Bradbury - 1864 - Počet stránok 324
...2)6.146128 3.073064 Ans. 1183.2 square feet. PROBLEM III. 106. To find the area of a trapezoid. RULE I. Multiply half the sum of the parallel sides by the perpendicular distance between them. Or, if the angles are known, we can use RULE II. Divide the trapezoid by a diagonal, and find the area... | |
 | Charles Davies - 1867 - Počet stránok 354
...ABCD, having two of its sides, AB, DC, parallel. The perpendicular CE is called the altitude. 322. To find the area of a trapezoid. Multiply half the sum of the two parallel sides by the altitude, and the product will be the area. (Bk. IV. Prop. VII.) EXAMPLES.... | |
 | William Mitchell Gillespie - 1868 - Počet stránok 530
...figures, tiro opposite sides of which are parallel. The content of a Trapezoid equals half the product of the sum of the parallel sides by the perpendicular distance between them. If the given quantities are the four sides a, 5, c, d, of which 5 and d are parallel ; then, making... | |
 | William Mitchell Gillespie - 1869 - Počet stránok 550
...figuies, U'o opposite sides of which are parallel. The content of a Trapezoid equals half the product of the sum of the parallel sides by the perpendicular distance between them. If the given quantities are the four sides a, b, c, d, of which b and d are parallel ; then, making... | |
 | Alfred Hiley - 1871 - Počet stránok 184
...of the parallel sides by the perpendicular distance between them, and divide the product by 2. Or, multiply half the sum of the parallel sides by the perpendicular distance between them. Note 1. — To find the sum of the parallel sides, when the area and the perpendicular distance are... | |
 | Shelton Palmer Sanford - 1872 - Počet stránok 404
...contents of a triangular lot whose sides are 56, 72 and 84 feet ? Ant. 221.23 sq. yd. ART. 361. To FIND THE AREA OF A TRAPEZOID. Multiply half the sum...sides by the perpendicular distance between them. 1. The parallel sides of a trapezoid are 36 and 24 feet, and its breadth 16 feet ; what is the area... | |
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To find the area of a trapezoid, multiply half the sum of the parallel sides by the perpendicular distance between them ; the product will be the area. 
